Problem : Write functions to:
🔰Reverse a list of elements.🔰Find the Sum of all elements in a list.🔰Check if a given elements exists in a list.
Solution:👇
Step 1: Define Functions:
👉The code defines three separate functions:
♦reverse_list(my_list): This function takes a list (my_list) as input and returns a new list with the elements in reverse order.
♦ sum_list(my_list): This function takes a list (my_list) as input and returns the sum of all the elements in the list.
♦element_exists(my_list, element): This function takes two arguments: a list (my_list) and an element (element). It checks if the givenelementexists within themy_listand returnsTrueif found,Falseotherwise.
Steps 2: List Slicing (Reverse Function):
👉The
reverse_listfunction utilizes Python's powerful list slicing syntax for efficient reversal. Here's how it works:
♦
my_list[::-1]: This expression creates a slice of the original list (my_list).
🔷The empty
:in the middle indicates the entire list is being sliced.
🔷-1specifies taking elements in reverse order (from the end to the beginning).
Step 3:
sum()function (Sum Function):👉The
sum_listfunction employs the built-insum()function in Python. It takes an iterable (like a list) as input and returns the sum of all its elements.Sstep 4:
inOperator (Element Exists Function):👉The
element_existsfunction leverages theinoperator in Python. The expressionelement in my_listevaluates toTrueif theelementis found within themy_list, andFalseif not.Step 5: Example Usage:
The code snippet demonstrates how to use these functions with an example list
my_list = [1, 2, 3, 4, 5]:
print(reverse_list(my_list)): Reverses the list and prints[5, 4, 3, 2, 1].print(sum_list(my_list)): Calculates the sum and prints15.print(element_exists(my_list, 3)): Checks for element 3 and printsTrue.

Good job keep it up
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